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10d^2+44d-30=0
a = 10; b = 44; c = -30;
Δ = b2-4ac
Δ = 442-4·10·(-30)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3136}=56$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-56}{2*10}=\frac{-100}{20} =-5 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+56}{2*10}=\frac{12}{20} =3/5 $
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